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12345 asked A power supply with internal resistance of 7 Ω applies a voltage of 25 V. If a load resistor of 52 Ω is in ser?
A power supply with internal resistance of 7 Ω applies a voltage of 25 V. If a load resistor of 52 Ω is in series with the power supply, then what is the current going through the circuit? Express the answer with two decimal places.
And got the following answer:
25 / 7 + 52 = 25 / 59 = 0.424 A